x^2-12x+36=-28

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Solution for x^2-12x+36=-28 equation:


Simplifying
x2 + -12x + 36 = -28

Reorder the terms:
36 + -12x + x2 = -28

Solving
36 + -12x + x2 = -28

Solving for variable 'x'.

Reorder the terms:
36 + 28 + -12x + x2 = -28 + 28

Combine like terms: 36 + 28 = 64
64 + -12x + x2 = -28 + 28

Combine like terms: -28 + 28 = 0
64 + -12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-64' to each side of the equation.
64 + -12x + -64 + x2 = 0 + -64

Reorder the terms:
64 + -64 + -12x + x2 = 0 + -64

Combine like terms: 64 + -64 = 0
0 + -12x + x2 = 0 + -64
-12x + x2 = 0 + -64

Combine like terms: 0 + -64 = -64
-12x + x2 = -64

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -64 + 36

Reorder the terms:
36 + -12x + x2 = -64 + 36

Combine like terms: -64 + 36 = -28
36 + -12x + x2 = -28

Factor a perfect square on the left side:
(x + -6)(x + -6) = -28

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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